The numbers are 71 and 19
Solution:
Let "x" be the larger number
Let "y" be the smaller number
Given that,
Sum of two numbers is 90
Therefore,
x + y = 90 ------ eqn 1
The larger number 14 more than 3 times the smaller number
Larger number = 14 + 3(smaller number)
x = 14 + 3y ------ eqn 2
Let us solve eqn 1 and eqn 2
Substitute eqn 2 in eqn 1
14 + 3y + y = 90
14 + 4y = 90
4y = 90 - 14
4y = 76
Divide both sides by 4
y = 19
Substitute y = 19 in eqn 2
x = 14 + 3(19)
x = 14 + 57
x = 71
Thus the numbers are 71 and 19
