Respuesta :

gmany

Answer:

[tex]\large\boxed{-y-3(-3y+5)=8y-15}[/tex]

Step-by-step explanation:

[tex]-y-3(-3y+5)\qquad\text{use the distributive porerty}\ a(b+c)=ab+ac\\\\=-y+(-3)(-3y)+(-3)(5)\\\\=-y+9y-15\qquad\text{combine like terms}\\\\=(-y+9y)-15\\\\=8y-15[/tex]

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