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  • 08-04-2018
  • Mathematics
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What are the zeros Of the function f(x)=(x^2-9)(x+1?

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Аноним Аноним
  • 08-04-2018
[tex]f(x) = (x^2 - 9)(x +1) [/tex]

when f(x) = 0,

[tex](x^2 - 9)(x +1) = 0[/tex]

[tex] (x - 3)(x+3)(x +1) = 0[/tex]

[tex] (x - 3) = 0 \text { or } (x+3)= 0 \text { or } (x +1) = 0 [/tex]

[tex]x = 3 \text { or } x= -3 \text { or } x= -1 [/tex]


The graph cuts the y-axis at (3, 0), (-3, 0) and (-1, 0)

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