imnotgoodatlife1419 imnotgoodatlife1419
  • 08-03-2018
  • Physics
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A 65 Kg roller-blade is accelerating at 5 m/s/s across the side walk. What force would be necessary for this acceleration to occur?

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skyluke89
skyluke89 skyluke89
  • 20-03-2018
Newton's second law states that the force applied to an object is equal to the product between the mass m of the object and its acceleration a:
[tex]F=ma[/tex]
Using [tex]m=65 kg[/tex] and [tex]a=5 m/s^2[/tex], we can find the value of the force applied to the roller-blade to obtain this acceleration:
[tex]F=(65 kg)(5 m/s^2)=325 N[/tex]
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