Solve for x. Use the completing the squares
method. Round decimals to the nearest tenth.
2x^2+16x=-18

Question

07-03-2018
Mathematics

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Solve for x. Use the completing the squares
method. Round decimals to the nearest tenth.
2x^2+16x=-18

Respuesta :

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rebelzane1 rebelzane1 · Answer 1 · 2018-03-07T20:05:00+01:00

rebelzane1 rebelzane1

07-03-2018

Hello there!
Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
[tex]x=-4± \sqrt{7} [/tex]
[tex]x≈-1.35424868, -6.64575131[/tex]

Hope this helps! :)
~Zain

Answer Link

Solve for x. Use the completing the squares method. Round decimals to the nearest tenth. 2x^2+16x=-18

Respuesta :

Otras preguntas

Solve for x. Use the completing the squares
method. Round decimals to the nearest tenth.
2x^2+16x=-18