4. An airplane at T(80,20) needs to fly to both U(20,60) and V(110,85). What is the shortest possible distance for the trip?
165units
170units
97units
169 units
is the answer A?
The distance formula for two points in a plane is D=sqrt( (x1-x2)^2 + (y1-y2)^2 ) From T to U D= sqrt((80-20)^2 + (20-60)^2) = 72.11 Then flying from U to V D= sqrt((20-110)^2 + (60-85)^2) = 93.4 So T to U to V = 72.11+93.4 = 165.5 BUT checking also T to V to U From T to V D= sqrt((80-110)^2 + (20-85)^2) = 71.6 Then from V to U D= sqrt((110-20)^2 + (85-60)^2) = 93.4 So from T to V to U = 165 Pretty much the same both directions So yes the answer is A
