jacobe0008 jacobe0008

08-02-2018
Mathematics

contestada

Solve for f.

h = f² + 2g

f=h±2g−−√

f=h±g√2

f=±h+2g−−−−−√

f=±h−2g−−

Respuesta :

13-02-2018

Solve for f.

h = f² + 2g

[tex]h= f^2+2g \\ \\ h-2g=f^2 \\ \\ \boxed{ \pm\sqrt{h-2g}= f} [/tex]

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