seairra2 seairra2
  • 11-01-2018
  • Mathematics
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Find the slope of the line that passes through (-1,6) and (15,6)

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hackermcpe
hackermcpe hackermcpe
  • 11-01-2018
Slope = [tex] \frac{Y2 - Y1}{X2 - X1} [/tex]
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6 - 6 = 0
15 - (-1) = 16
0 / 16 = 0
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You have a slope of 0, meaning that this is a straight horizontal line
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