zacmasto6800 zacmasto6800
  • 11-01-2018
  • Mathematics
contestada

Give the equation of the circle centered at the origin and passing through the point , 0−3 .

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W0lf93
W0lf93 W0lf93
  • 24-01-2018
x^2 + y^2 = 9  
The general equation for a circle of radius r centered at point (h,k) is 
(x - h)^2 + (y - k)^2 = r^2  
Since we want it centered at the original, h and k are both 0, so the equation simplifies to: 
x^2 + y^2 = r^2 
 Substituting the known values for the given point gives: 
x^2 + y^2 = r^2
 0^2 + 3^2 = r^2
 0 + 9 = r^2
 9 = r^2
 3 = r
 
 So we have
 x^2 + y^2 = 3^2
 or
 x^2 + y^2 = 9

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