The Corrected Problem is :
2:x and 12:18 identify the value of x that makes each pair of ratios equivalent .
Solution:
If a pair of Ratios are equivalent then we can write
[tex] \frac{2}{x}=\frac{12}{18}\\
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\text{Simplify we get}\\
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12x=36\\
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\text{Divide both the sides by 12 we get}\
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\frac{12x}{12}=\frac{36}{12}\\
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x=3\\
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\text{Hence the required value of x is 3}\\ [/tex]
