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09-01-2018
Mathematics

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p(x)=x^2-2x-8 and q(x)=x^2-5x+14 what are the zeros of p(x) +q(x)?

pxx22x8 and qxx25x14 what are the zeros of px qx class=

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Аноним Аноним

09-01-2018

x^2 - 2x - 8 = 0
(x - 4)(x + 2) = 0

x = -2, 4 Answer

x^2 - 5x + 14
(x - 7)(x + 2) + 0

x = -2, 7 Answer

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