aryanancruz2932 aryanancruz2932

09-01-2018
Physics

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An object is dropped from a height h. during the final second of its fall, it traverses a distance of 41.2 m. what was h?

Respuesta :

carlosego carlosego

19-01-2018

41.2 = h-1/2g(t-1)^2
{-h = -1/2gt^2-1/2g+g*t-41.2
{h = 1/2gt^2
summing them up
0 = -1/2g+g*t-41.2
41.2 +4.9 = g*t
t = 46.1/9.8 = 4.70 sec
h = 1/2gt^2 =4.9*(4.70^2) = 108.241 m

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