amylowes102 amylowes102

09-12-2017
Mathematics

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Gradient of a straight line that is perpendicular to y = 4x + 2

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tynollette tynollette

09-12-2017

if a line's slope is [tex] \frac{a}{b} [/tex], the slope of the perpendicular line is [tex] -\frac{b}{a} [/tex]
in this case, the given line has a slope 4, which is 4/1, so the perpendicular line has a slope/gradient [tex] -\frac{1}{4} [/tex]

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