dragonladyjo2053 dragonladyjo2053
  • 09-12-2017
  • Chemistry
contestada

Calculate the temperature, in k, of 2.20 moles of gas occupying 3.30 l at 3.50 atm.

Respuesta :

kenmyna
kenmyna kenmyna
  • 19-12-2017
From  idea  gas  equation  that is   PV=nRT
T= temperature  in kelvin
R=gas   cosntant(0.0821atm/k/mol)
P=pressure(3.5atm)
V=volume 3.30L
n=number  of  moles (2.20mole)
T  is  therefore  =PV/nR
T={(3.50 x3.30) /(2.20 x 0.0821)}=63.95k
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