diixnx77 diixnx77
  • 09-11-2017
  • Mathematics
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factor 10b3+4b2−15b−6 completely

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choixongdong
choixongdong choixongdong
  • 09-11-2017
10b^3+4b^2−15b−6
= 2b^2(5b + 2) - 3(5b + 2)
= (2b^2 - 3)
(5b + 2)


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