Respuesta :

Nadeshiko
We can solve this system of equations using substitution.

2y + 2x = 8

Solve for x.

2x = -2y + 8

Divide all terms by 2.

x = -y + 4

Take the equation x = -y + 4 and substitute it into the second system of equation.

2y - 4x = 2

2y - 4(-y + 4) = 2

Simplify by distributing.

2y + 4y - 16 = 2

Combine like terms.

6y - 16 = 2

6y = 18

y = 3


Now that you know the numerical value of y, substitute y with 3 in both equations to find x.

1) 2y + 2x = 8

2(3) + 2x = 8

6 + 2x = 8

2x = 2

x = 1

2) 2y - 4x = 2

2(3) - 4x = 2

6 - 4x = 2

-4x = -4

x = 1

The value of x is 1, and the value of y is 3.

Solution: B) (1, 3)

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