Respuesta :

LammettHash
Since the variance of a Poisson distribution with rate parameter [tex]\lambda[/tex] is [tex]\lambda^2[/tex], we know that [tex]\lambda=\sqrt3[/tex]. So,

[tex]\mathbb P(X=2)=\dfrac{e^{-\sqrt3}(\sqrt3)^2}{2!}=\dfrac3{2e^{\sqrt3}}\approx0.2654[/tex]