ttt43
ttt43
06-09-2017
Mathematics
contestada
I do not know how to do this
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WojtekR
WojtekR
06-09-2017
[tex]u+ka=ba\\\\u=ba-ka\\\\u=a(b-k)\quad|:(b-k)\\\\\boxed{\frac{u}{b-k}=a}\qquad\qquad\text{when}\quad b\neq k[/tex]
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