Answer:
centre = (- 2, 0 ) , radius = [tex]\sqrt{13}[/tex]
Step-by-step explanation:
The equation of a circle in standard form is
(x - h )² + (y - k )² = r²
(h, k ) are the coordinates of the centre and r is the radius
given the equation
(x + 2)² + y² = 13 , that is
(x - (- 2) )² + (y - 0)² = ( [tex]\sqrt{13}[/tex] )² ← in standard form
with h = - 2 , k = 0 , r = [tex]\sqrt{13}[/tex] , that is
centre = (- 2, 0 ) and radius = [tex]\sqrt{13}[/tex]
