SillySallie SillySallie
  • 07-08-2017
  • Mathematics
contestada

Turn 2800=1900(1+0.025)^n into a logarithm

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jdoe0001 jdoe0001
  • 07-08-2017
[tex]\bf \textit{exponential form of a logarithm}\\\\ log_{{ a}}{{ b}}=y \implies {{ a}}^y={{ b}}\\\\ -------------------------------\\\\ %2800=1900(1+0.025)^n into a logarithm 2800=1900(1+0.025)^n\implies \cfrac{2800}{1900}=(1.025)^n\implies \cfrac{28}{19}=1.025^n \\\\\\ \begin{cases} a=1.025\\ b=\frac{28}{19}\\ \end{cases}\implies log_{1.025}\left( \frac{28}{19} \right)=n[/tex]
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