Respuesta :

m (O) = M x n

M (O) = 16g/mol

n (O) = 3 x n (NaHCO3)

n (NaHCO3) = m/M

m (NaHCO3) = 0.72g

M (NaHCO3) = 23 + 1 + 14 + 16 x 3 = 86g/mol

n (NaHCO3) = 0.72/86 = 0.008372mol

n (O) = 3 x 0.008372 = 0.02512

m (O) = 16 x 0.02512 = 0.402g

The grams of oxygen are in 0.72 g of NaHCO3 is 0.41 grams .

The compound is NaHCO₃.

The molar mass of NaHCO₃ = 23 + 1 + 12 + 48 = 84 g

Therefore,

84 grams of  NaHCO₃ has 48 grams of Oxygen

0.72 grams of  NaHCO₃ will have ? of Oxygen

cross multiply

mass of oxygen = 0.72 × 48 / 84

mass of oxygen = 34.56 / 84

mass of oxygen = 0.41142857142

mass of oxygen ≈ 0.41 grams

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