Quadrant II is correct:) i just answered this question on edge- nuity
Answer:
( Quadrant II )P' located.
Step-by-step explanation:
Given : Point P is located at (–4, –7) P is reflected across the x-axis to create P'.
To find : In which quadrant is P' located.
Solution : We have given that P (-4, -7 )
Here we can see P (-4, -7) lies in third quadrant.
if we reflect it across x -axis tp create P' , it would be in Second quadrant.
P (-4, -7) would be P'( -4 , 7) .
Therefore,( Quadrant II )P' located.
