Respuesta :

irspow
If you factor the denominator of the left multiplicand...

[(a-4)(a+3)]/[a(a-4)]  you can see that the (a-4)s cancel out leaving:

(a+3)/a

now you have

(a+3)/a * 2a^3/((a+3)(a-1))  so the (a+3)s cancel out leaving:

1/a * 2a^3/(a-1)  which is:

2a^3/(a(a-1))  so now a^1 cancel leaving

2a^2/(a-1)