larryahill1966 larryahill1966

08-06-2017
Mathematics

contestada

possible values of x in 6x^2 + 432 = 0

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konrad509 konrad509

08-06-2017

[tex]6x^2 + 432 = 0 \\ x^2+72=0\\ x^2=-72\\ x=-\sqrt{-72} \vee x=\sqrt{-72}\\ x=-6\sqrt2 i \vee x=6\sqrt 2 i [/tex]

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DrDillon12 DrDillon12

17-11-2021

x = + & - 6 /2i

Correct on Plato ;)

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