john8426 john8426
  • 08-06-2017
  • Mathematics
contestada

What is the GCF of 48m5n and 81m2n2?
3mn
3m2n
48m2n
129m5n2

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TheHero
TheHero TheHero
  • 18-06-2017
81m^5 n /48 m^2 * n^2 = 27/16  m^3/n (so 3 is common factor for the coefficient)

so common factor = 81/27 = 3 ,   m^5/m^3 = m^2 , n^2/n = n

common factor = 3m^2n (B)
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diesel2004 diesel2004
  • 28-04-2020

Answer

b for edge2020

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