The mean amount of time needed to microwave thaw a particular frozen dinner in preparation for convection cooking is 5.68 minutes. the standard deviation of thaw times is 0.95 minutes. what proportion of the meals will take between 4.36 and 7 minutes to thaw?
We need to determine the values of the z-scores of the given data. (4.36 minutes) z-score = (4.36 - 5.68)/0.95 = -1.39 Which has an equivalent percentage of 8.2%. (7 minutes) z-score = (7 - 5.68) / 0.95 = 1.39 Which has an equivalent percentile of 92%.
Subtracting the two values will give us an answer of 83.8%.
