This is the concept of algebra, we are required to solve the given expression; 32^(2c)=8^(c+7) this can be written as: 2^[5(2c)]=2^[3(c+7) applying the natural logs we shall get [5(2c)]ln2=[3(c+7)]ln2 The ln 2 will cancel on from both sides and we shall have: 5(2c)=3(c+7) 10c=3c+21 To make c the subject we begin by subtracting 3c from both sides 10c-3c=3c+21-3c 7c=21 dividing both sides by 7 we get: (7c)/7=21/7 c=3 The answer is c=3
