michaela05mm michaela05mm
  • 08-05-2017
  • Mathematics
contestada

A circle has a diameter that starts
at (3, 7) and ends at (7, 3). What is the radius of the circle rounded to the nearest tenth?

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apologiabiology
apologiabiology apologiabiology
  • 08-05-2017
find the distance between those points

diameter/2=radius


distance betwen (x1,y1) and (x2,y2) is
[tex]D= \sqrt{(x2-x1)^2+(y2-y1)^2} [/tex]

given
(3,7) and (7,3)

[tex]D= \sqrt{(7-3)^2+(3-7)^2} [/tex]
[tex]D= \sqrt{(4)^2+(-4)^2} [/tex]
[tex]D= \sqrt{16+16} [/tex]
[tex]D= \sqrt{32} [/tex]
D=4√2

diameter/2=(4√2)/2=2√2

radius is 2√2
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