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C0RA C0RA
  • 08-05-2017
  • Mathematics
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What is the correct simplification of the expression a to the 6th power times b to the 3rd power all over a to the 4th power times b to the second power?

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tonb
tonb tonb
  • 11-05-2017
[tex] \frac{a^{6} b^{3}}{a^{4} b^{2}} = a^{2}b[/tex]

The powers cancel each other out. For example (a.a.a.a.a.a)/(a.a.a.a) = a.a
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