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06-05-2017
Mathematics

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A $30,000 car depreciates in value 12% a year. How much will the car be worth in 5 years?

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Аноним Аноним

06-05-2017

It will be worth $15,832

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06-05-2017

f=ir^t, f=final value, i=initial value, r=rate, t=time, in this case:

f=30000((100-12)/100)^t

f=30000(0.88)^t so

f(5)=30000(0.88)^5

f(5)=$15831.96 to nearest cent

Answer Link

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