Data:
M (molarity) = 1.75 M (mol/L)
m (mass) = 35 g
MM (molar Mass) of NaCl = 58.44 g/mol
V (volume) = ? (in liters)
Formula:
[tex]M = \frac{m}{MM*V} [/tex]
Solving:
[tex]M = \frac{m}{MM*V} [/tex]
[tex]1.75 = \frac{35}{58.44*V} [/tex]
[tex]1.75*58.44V = 35[/tex]
[tex]102.27V = 35[/tex]
[tex]V = \frac{35}{102.27} [/tex]
[tex]\boxed{\boxed{V \approx 0.34\:L}}\end{array}}\qquad\quad\checkmark[/tex]
