harrydale08 harrydale08

10-02-2015
Mathematics

contestada

P=3a+2b^2 (Make 'a' the subject)

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konrad509 konrad509

10-02-2015

[tex]P=3a+2b^2\\ 3a=P-2b^2\\ a=\dfrac{P-2b^2}{3}[/tex]

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