help358 help358
  • 09-02-2017
  • Mathematics
contestada

In triangle JKL, solve for x

In triangle JKL solve for x class=

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samszy2805 samszy2805
  • 09-02-2017
for this question you need to apply the trigonometric ratios with cos 27 degrees
cos 27 = [tex] \frac{34}{x} [/tex]
0.891x = 34cm
∴x = 38.159cm

please mark as brainliest

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valerialynn58
valerialynn58 valerialynn58
  • 16-08-2018

38.16 = when rounded

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