Ronnieking17 Ronnieking17

07-02-2017
Mathematics

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How do I reflect over x=3 ??

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23dancer3 23dancer3

07-02-2017

This last claim is because x can be thought of as 2+a, where "a" could be negative! Now x needs to go to 2-a, but solveing for "a" in x=2+a gives a=x-2, so the new x is
2-a = 2-(x-2) = 4-x.

(-1,1) => (5,1)
(0,4) => (4,4)
(-3,4) => (7,4)

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