lindseyhajdukovich
lindseyhajdukovich lindseyhajdukovich
  • 07-02-2017
  • Mathematics
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(6 - d)(d 2 - 5 + 3d)

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juanny1818
juanny1818 juanny1818
  • 07-02-2017
(6−d)(d^2−5+3d)=(6+−d)(d^2+−5+3d)=(6)(d^2)+(6)(−5)+(6)(3d)+(−d)(d^2)+(−d)(−5)+(−d)(3d)=6d^2−30+18d−d^3+5d−3d^2
= −d3^+3d^2+23d−30






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