ajthegreat ajthegreat
  • 06-02-2017
  • Chemistry
contestada

The moles in 196.5 grams of Zn(NO3)2

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behnaz
behnaz behnaz
  • 06-02-2017
Zn(NO3)2 = 65.38+ 2{14+ 3(16)} = A
196.5 gr ^ 1/A = your answer mole
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