Respuesta :

loneguy

[tex]\text{Given that,}~ \text{center,(h,k)} = (-3,2)~ \text{and radius}~ r = 4\\\\\text{Equation of circle,}\\\\~~~~~~~(x-h)^2 +(y-k)^2 = r^2\\\\\implies (x+3)^2 +(y-2)^2 = 4^2\\\\\implies (x+3)^2 +(y-2)^2 = 16[/tex]

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