Step-by-step explanation:
[tex] log_{5}(x + 9) = log_{5}(x + 5) + 1[/tex]
[tex] \frac{ log(x + 9) }{ log(5) } = \frac{ log(x + 5) }{ log(5) } + 1[/tex]
[tex] log(x + 9) = log(x + 5) + log(5) [/tex]
[tex] log(x + 9) = log(5x + 25) [/tex]
[tex]x + 9 = 5x + 25[/tex]
[tex]x = - 4[/tex]
If we plug it in, it is true
