Respuesta :

Hrishii

Answer:

[tex] 56\: in^2[/tex]

Step-by-step explanation:

  • Surface area of the net = 4* Area of one triangle + Area of square

  • [tex] = 4*\frac{1}{2}*4*5 + (4)^2[/tex]

  • [tex] = 40 + 16[/tex]

  • [tex] = 56\: in^2[/tex]