Seudónimo Seudónimo
  • 09-04-2022
  • Mathematics
contestada

solve .-. ~
[tex] \\ \\x - \frac{1}{2} \geqslant 43 \\ [/tex]

thankyou .-.​

Respuesta :

Аноним Аноним
  • 09-04-2022

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's solve ~

[tex]\qquad \tt \dashrightarrow \:x - \dfrac{1}{2} \geqslant 43 [/tex]

[tex]\qquad \tt \dashrightarrow \:x \geqslant43 + \dfrac{1}{2} [/tex]

[tex]\qquad \tt \dashrightarrow \:x \geqslant \dfrac{86 + 1}{2} [/tex]

[tex]\qquad \tt \dashrightarrow \:x \geqslant \dfrac{87}{2} [/tex]

hope this helps Belinda aunty ~

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