luisserrato7118 luisserrato7118

08-04-2022
Chemistry

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what is the pH of a solution that has a [H+]=1.75x10^-11

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loneguy loneguy

08-04-2022

[tex]pH = - \log[\text{H}^{+}] = -\log \left(1.75 \times 10^{-11} \right) = 10.757[/tex]

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