hardimondamien9 hardimondamien9
  • 07-04-2022
  • Mathematics
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Looking for good answer on this

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tackt11 tackt11
  • 07-04-2022
-6/4+x (the first one)
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loneguy
loneguy loneguy
  • 07-04-2022

[tex]\dfrac{6x-24}{16-x^2}\\\\=\dfrac{6(x-4)}{4^2 -x^2}\\\\=\dfrac{6(x-4)}{(4+x)(4-x)}\\\\=-\dfrac{6(x-4)}{(x+4)(x-4)}\\\\=-\dfrac{6}{x+4}[/tex]

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