The concentration of A is initially 0.150 M before it proceeds to equilibrium. The system is at 298 K. What is the equilibrium concentration of B

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shardaeheyward2490 shardaeheyward2490

07-04-2022
Chemistry

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The concentration of A is initially 0.150 M before it proceeds to equilibrium. The system is at 298 K. What is the equilibrium concentration of B

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okpalawalter8 okpalawalter8 · Answer 1 · 2022-04-13T12:12:37+02:00

For a concentration of is initially 0.150 M before it proceeds to equilibrium, the equilibrium concentration of B is mathematically given as

x=3.0*10^{-7}m

What is the equilibrium concentration of B?

Generally, the equation for the change in Gibbs free energy is mathematically given as

dG=-RTInK

Therefore

31.5*10*^{3}=-(8.314)(298)(ink)

K=3*10^(-6)

Eqution

A--->B

K=x/0.1-x

x=3.0*10^{-7}m

In conclusion, the equilibrium concentration

x=3.0*10^{-7}m