[tex]P(x)=4x^3-6x^2+ax-2\\\\P(3)=2\\\\\implies 4\cdot 3^3-6 \cdot 3^2 +3a-2=2\\\\\implies 108-54-4 +3a=0\\\\\implies 50+3a=0\\\\\implies a = -\dfrac{50}3[/tex]
Answer:
The value of a = -16.6.... or -16.7
Step-by-step explanation:
Given :
P(3) = 2
P(x) = 4x^3 - 6x^2 + ax – 2
=> 2 = 4(3)³ - 6(3)² + a(3) -2
=> 2 = 4(27) - 6(9) +3a - 2
=> 2+2 = 108 - 54 +3a
=> 4 = 54 + 3a
=> 4-54 = 3a
=> -50 = 3a
=> -50/3 = a
=> a = -16.6.... or -16.7
