Answer:
D) [tex]x=\frac{5}{3}[/tex] and [tex]x=-4[/tex]
Step-by-step explanation:
Factor by grouping
[tex]3x^2+7x-20=0\\\\3x^2+12x-5x-20=0\\\\3x(x+4)-5(x+4)=0\\\\(3x-5)(x+4)=0[/tex]
Solve each factor using the Zero Product Property
[tex]3x-5=0\\\\3x=5\\\\x=\frac{5}{3}[/tex]
[tex]x+4=0\\\\x=-4[/tex]
Thus, [tex]x=\frac{5}{3}[/tex] and [tex]x=-4[/tex] are the solutions
