Answer:
f^-1(x) = (x +5)/3
also = 1/3 x + 5/3
Step-by-step explanation:
Just to be clear, the ^-1 has nothing to do with negative exponents. It just unfortunately looks the same as a negative exponent.
Anyway, there's three basic steps. First write y instead of f(x). Then switch the x and y. Then solve for y.
f(x) = 3x - 5
write y in place of f(x).
y = 3x - 5
SWITCH x and y.
x = 3y - 5
SOLVE for y.
-3y + x = -5
-3y = -x - 5
y = (-x - 5)/-3
y = (x + 5)/3
OR
y = (1/3)x + 5/3
f^-1(x) = 1/3 x + 5/3
