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  • 08-02-2022
  • Mathematics
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HELP ME AGAIN!!!!! I NEED 100% (ALGEBRA)

HELP ME AGAIN I NEED 100 ALGEBRA class=

Respuesta :

semsee45
semsee45 semsee45
  • 08-02-2022

Answer:

[tex](foh)(x)=-x^2 +6x+31[/tex]

Step-by-step explanation:

[tex]\huge f(x)=13-x\ \ \ \ \ \ h(x)=x^2-6x-18 \\ \\(foh)(x)=f[h(x)]=13-(x^2-6x-18)=-x^2 +6x+31[/tex]

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