Respuesta :

[tex]\\ \tt\hookrightarrow p(2)=3(2)^6-5(2)^5-2+7[/tex]

[tex]\\ \tt\hookrightarrow p(2)=3(64)-5(32)+5[/tex]

[tex]\\ \tt\hookrightarrow p(2)=192-160+5[/tex]

[tex]\\ \tt\hookrightarrow p(2)=32+5[/tex]

[tex]\\ \tt\hookrightarrow p(2)=37[/tex]

Option B is correct

fieryanswererft

Answer:

B. 37

explanation:

Just replace x with the given value unit.

→ p(x)= 3x^6 - 5x^5 - x + 7

→ p(2)= 3(2)^6 - 5(2)^5 - (2)+ 7

→ p(2) = 3(64) - 5(32) - 2 + 7

→ 192 - 160 - 2 + 7

→ 37