Answer:
A(3,-1) and B( -2,1)
Step-by-step explanation:
2x+5y=1. , or. y=(1–2x)/5………….(1)
x^2+5xy-4y^2+10=0…………………..(2)
Putting y=(1–2x)/5 from eqn. (1)
x^2+5x.(1–2x)/5–4/25.(1–2x)^2 +10=0
or. 25x^2+25x.(1–2x)-4.(1+4x^2–4x)+250 = 0
or. 25x^2+25x-50x^2–4–16x^2+16x+250=0
or. 41x^2–41x-246=0
or x^2– x - 6=0
or. (x-3).(x+2)=0
=> x= 3 or -2
But y=(1–2x)/5
=> y= (1–6)/5 or. (1+4)/5
hence, y= -1. or. 1
