deniciasookraj2007 deniciasookraj2007

08-01-2022
Physics

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1) A spring with a spring constant of 0.70 N/m is stretched 1.5 m. What was the force? 2) The same spring is stretched 5 m. What was the force?

1 A spring with a spring constant of 070 Nm is stretched 15 m What was the force 2 The same spring is stretched 5 m What was the force class=

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supnickname supnickname

08-01-2022

Answer:

K= F/∆l
F=K•∆l
∆l=F/K
so we know that the K is 0.70N/m
the ∆l which is the elongation is 1.5 m
to find the force which is F u have to apply the formula.
by applying the formula you get 1.05N
for the second force you get 3.5N

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